Online Sic Bo Strategies 2022
2022 Strategies of Playing Online SIc Bo
1. Problem statement
The player first selects the number of terracotta coins bet, and then chooses to buy the big or the small. After confirming, the 3 dice will be randomly generated by the system program to generate 3 random numbers from 1 to 6. If the three numbers are the same, no matter if they buy the big Or buy small players to get back the amount of terracotta coins bet; if they are different, add these three numbers, 4~10 points are small, 11~17 are big, if the player presses the right size, get the amount of bet Terracotta coins.
Now three questions are raised from this:
1. Buy big and win more or buy small and win more?
2. Is it possible to make money with this gambling method?
3. How can I make more money by playing? Is there a way of playing that only makes money but not loses?
2. Simplification and assumptions
Assume that the number of terracotta coins owned by the player is M (M is a natural number)
The number of terracotta coins betted every time is N (N>=1000, N is a natural number)
When buying small, set f=-1; when buying big, set f=1
Suppose the points of these three dice are a, b, c (a, b, c are natural numbers from 1 to 6)
When a=b=c, that is, if the dealer rolls a full dice (three dice points are the same), it will take all the big and small dice, set g=0;
When a+b+c=4~10, it will open small, g= -1;
When a+b+c=11~17, it is open, g=1.
h=1&&f*g=1 || h= -1&&f*g=0|-1
After 1 round, the player’s number of terracotta coins is: M+h*N
After the nth round, the player’s number of terracotta coins is: M+h1*N1+h2*N2+….+hn*Nn.
3. The Model And Its Solution
1. First, analyze the number of dice in a single game
Since the original code of the system is unknown, it can be assumed that the number of points from 1 to 6 on each dice is random. For the three dice, there are two combinations: XXX, XXY, and XYZ. XXX includes only one, and XXY includes There are 3 types of XYX and YXX, and 6 combinations of XYZ. The following table can list the number of small, take all, and big:
Points, Combination Method, Small, All Eat, Big
3 111 0 1 0
4 112 3 0 0
5 113, 122 6 0 0
6 114, 123, 222 9 1 0
7 115, 124, 133, 223 15 0 0
8 116, 125, 134, 224, 233 21 0 0
9 126, 135, 144, 225, 234, 333 24 1 0
10 136, 145, 226, 235, 244, 334 27 0 0
11 146, 155, 236, 245, 335, 344 0 0 27
12 156, 246, 255, 336, 345, 444 0 1 24
13 166, 256, 346, 355, 445 0 0 21
14 266, 356, 446, 455 0 0 15
15 366, 456, 555 0 1 9
16 466, 556 0 0 6
17 566 0 0 3
18 666 0 1 0
Total: 105 6 105
The total combination of three dice is 6*6*6=216 kinds
The probability of taking it all is: 6/216=1/36=2.78%
The probability of opening up is: 105/216=35/72=48.61%
The probability of opening a small one is: 105/216=35/72=48.61%
It can be seen that for a single game, the chances of opening a large and small opening are the same.
2. How to place bets by junior players:
At the beginning, you usually play back like this: a certain number of bets in each round. In this case, the number of terracotta coins bet N is certain, then after n rounds, the number of terracotta coins of the player is: M+(h1+h2+….+hn)*N
If you keep buying big, assuming that n is big, then:
If you keep buying small, the same is true;
The same goes for buying large and small arbitrarily.
Therefore, after n rounds, the player’s number of terracotta coins is: M*97.22%
It can be seen that in this way, when the number of bets in each round is fixed or not much different, when many rounds are played, the number of terracotta coins of the player will only decrease, leaving only 97.22% of the principal, and the other 2.78% will be washed by the dealer. gone. :(
3. How to play for experienced players:
1) The number of terracotta coins bet is x=N;
2) The size bought is opposite to the one opened in the previous set;
3) If you win, continue to step 1), if you lose, continue;
4) The number of terracotta coins bet doubled x=2*x, continue to step 2);
For this kind of gameplay, it seems that you only make no losses, but if you are unlucky and open n large ones, although this is a small probability, you will be gambled out and you will lose your money.
At this time, ignoring the 2.78% that the dealer washes away, and the probability of opening a large opening and a small opening can be regarded as 50%
The probability of opening n large/small ones is 1/2^n. Assuming that the terracotta coins are purchased at this time, the number of terracotta coins bet is N*2^n, and the number of losses is N*(1+2 ^1+……+2^(n-1))=N*(2^n-1), when n is large, the 1 can be ignored, then the remaining number of terracotta coins is MN*2^(n +1), that is, N*2^(n+1) of funds will be invested in the nth round. If the remaining funds are less than N*2^(n+2), once the money is lost, the money will be lost.
If n is not greater than 10, and N=1000, the probability of opening 10 large/small ones in succession is 1/1024 and less than 0.1%, and the required capital is about 2 million to ensure that the gamble will not be run out. Although playing this way seems very safe, in fact, the money earned in each round is very small.
Can you win money by betting like this? The answer is no, because each bet is a completely independent process, set to P, regardless of whether the bettor buys the big or the small, the betting event is set to Q, and the whole process of betting open the dice is P*Q, It is still a completely independent process, so when the number of times of playing is a lot, the number of terracotta coins of the player will not increase, and 2.78% will be washed away by the dealer, and there is no way of only making money without losing money.
Through the analysis of mathematical methods, we found that in this game, the winner is always the banker. This is the reason why ten bets and nine loses. The same is true for gambling and lottery. Therefore, you should not be too obsessed with it and work hard to do your job. Work is the way to success.
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